C语言实现桥接模式

最新推荐文章于 2025-09-09 19:08:39 发布

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这篇博客介绍了一种在C++中通过结构体和函数指针实现不同类型的对象调用相应行为的方法。代码示例展示了如何定义`BodyBuilder`和`BailPlaying`结构体，以及如何通过`PlayRequest`结构体来根据类型调用对应的`play`方法。在`main`函数中，创建了一个`BodyBuilder`实例，并通过`PlayRequest`调用了`body_building`函数。

#include <stdio.h>
#include <stdlib.h>
typedef struct _BodyBuilder
{
    void (*play)();
} BodyBuilder;
typedef struct _BailPlaying
{
    void (*play)();
} BailPlaying;
typedef struct _PlayRequest
{
    int type;
    void *pPlaying;
} PlayRequest;
#define BODY_BUILDER_TYPE 0
#define BAIL_PLAYING_TYPE 1
void person_playing(PlayRequest *pPlayRequest)
{
    if ((NULL == pPlayRequest) || (NULL == pPlayRequest->pPlaying))
    {
        return;
    }
    switch (pPlayRequest->type)
    {
    case BODY_BUILDER_TYPE:
        ((BodyBuilder *)pPlayRequest->pPlaying)->play();
        break;
    case BAIL_PLAYING_TYPE:
        ((BailPlaying *)pPlayRequest->pPlaying)->play();
        break;
    }
}
void body_building() 
{
    printf("body building!\n");
}
int main() 
{
    BodyBuilder bodyBuilder;
    bodyBuilder.play = body_building;
    PlayRequest request;
    request.type = BODY_BUILDER_TYPE;
    request.pPlaying = &bodyBuilder;
    person_playing(&request);

    return 0;
}