No6 Java

题目：

The sum of the squares of the first ten natural numbers is,

1 ² + 2 ² + ... + 10 ² = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10) ² = 55 ² = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

 

翻译：

前10个自然数的平方的和是，1 ² + 2 ² + ... + 10 ² = 385

而他们的和的平方是，(1 + 2 + ... + 10) ² = 55 ² = 3025

他们的差就是3025 385 = 2640。

找出前100个自然数的这种差。

 

解题思路：

说实话，这题和第一题的难度一样低，直接上代码。

 

代码：

int sumOfSquares = 0; int squareOfSum = 0; for (int i = 1; i <= 100; i++) { sumOfSquares += i * i; squareOfSum += i; } squareOfSum *= squareOfSum; System.out.println(squareOfSum - sumOfSquares);