程序及代码
#include<iostream>
#include<cmath>
double distance3(double a,double b,double c,double d)
{
double ds;
ds=sqrt((a-c)*(a-c)+(b-d)*(b-d));
return ds;
}
using namespace std;
class Cpoint
{
public:
Cpoint(double xx=0,double yy=0);
double distance1(Cpoint x1);
friend double distance2(Cpoint &,Cpoint &);
private:
double x;
double y;
};
Cpoint::Cpoint(double xx,double yy)
{
x=xx;
y=yy;
}
double Cpoint::distance1(Cpoint x1)
{
double d;
d=sqrt((x-x1.x)*(x-x1.x)+(y-x1.y)*(y-x1.y));
cout<<d<<endl;
}
double distance2(Cpoint &t1,Cpoint &t2)
{
double d;
d=sqrt((t1.x-t2.x)*(t1.x-t2.x)+(t1.y-t2.y)*(t1.y-t2.y));
cout<<d<<endl;
}
int main()
{
Cpoint c1(2,2);
Cpoint c2(1,1);
c1.distance1(c2);
distance2(c1,c2);
cout<<distance3(1,1,2,2)<<endl;
}
运行结果
程序及代码
#include<iostream>
using namespace std;
class Date; //对Date类的提前引用声明
class Time
{
public:
Time(int h,int m,int s);
void add_a_second(Date &); //增加1秒,1秒后可能会到了下一天,乃到下一月、下一年
void display(Date &); //显示时间,格式:月/日/年 时:分:秒
private:
int hour;
int minute;
int sec;
};
class Date
{
public:
Date(int m,int d,int y);
friend class Time; //Time为Date的友元类
private:
int month;
int day;
int year;
};
Time::Time(int h,int m,int s)
{
hour=h;
minute=m;
sec=s;
}
Date::Date(int m,int d,int y)
{
month=m;
day=d;
year=y;
}
void Time::add_a_second(Date &d1)
{
int a[12]={31,28,31,30,31,30,31,31,30,31,30,31};
sec++;
if(sec>=60)//显示时间,格式:月/日/年 时:分:秒
{
minute++;
sec-=60;
if(minute>=60)
{
hour++;
minute-=60;
if(hour>=24)
{
d1.day++;
hour-=24;
if(d1.month!=2)
{
int i;
i=d1.month;
if(d1.day>a[i])
{
d1.month++;
d1.day-=a[i];
if(d1.month>12)
{
d1.year++;
d1.month-=12;
}
}
}
if(d1.month==2)
{
if(d1.year%4==0&&d1.year%100!=0||d1.year%400==0)
{
if(d1.day>29)
{
d1.month++;
d1.day-=29;
if(d1.month>12)
{
d1.year++;
d1.month-=12;
}
}
}
else
{
if(d1.day>28)
{
d1.month++;
d1.day-=28;
if(d1.month>12)
{
d1.year++;
d1.month-=12;
}
}
}
}
}
}
}
}
void Time::display(Date &d1)
{
cout<<d1.month<<"/"<<d1.day<<"/"<<d1.year<<" "<<hour<<":"<<minute<<":"<<sec<<endl;
}
int main( )
{
Time t1(23,59,32);
Date d1(12,31,2013); //测试时,再试试Date d1(2,28,2013)会如何
for(int i=0; i<=100; i++)
{
t1.add_a_second(d1);
t1.display(d1);
}
return 0;
}
运行结果