Given an integer array nums
, design an algorithm to randomly shuffle the array. All permutations of the array should be equally likely as a result of the shuffling.
Implement the Solution
class:
Solution(int[] nums)
Initializes the object with the integer array nums.int[] reset()
Resets the array to its original configuration and returns it.int[] shuffle()
Returns a random shuffling of the array.
Example 1:
Input ["Solution", "shuffle", "reset", "shuffle"] [[[1, 2, 3]], [], [], []] Output [null, [3, 1, 2], [1, 2, 3], [1, 3, 2]] Explanation Solution solution = new Solution([1, 2, 3]); solution.shuffle(); // Shuffle the array [1,2,3] and return its result. // Any permutation of [1,2,3] must be equally likely to be returned. // Example: return [3, 1, 2] solution.reset(); // Resets the array back to its original configuration [1,2,3]. Return [1, 2, 3] solution.shuffle(); // Returns the random shuffling of array [1,2,3]. Example: return [1, 3, 2]
Constraints:
1 <= nums.length <= 200
-106 <= nums[i] <= 106
- All the elements of
nums
are unique. - At most
5 * 104
calls in total will be made toreset
andshuffle
.
代码(Rust):
use rand::{thread_rng, Rng};
struct Solution {
origin: Vec<i32>,
list: Vec<i32>,
}
/**
* `&self` means the method takes an immutable reference.
* If you need a mutable reference, change it to `&mut self` instead.
*/
impl Solution {
fn new(nums: Vec<i32>) -> Self {
Self {
origin: nums.clone(),
list: nums,
}
}
/** Resets the array to its original configuration and return it. */
fn reset(&self) -> Vec<i32> {
self.origin.clone()
}
/** Returns a random shuffling of the array. */
fn shuffle(&mut self) -> Vec<i32> {
let mut rng = thread_rng();
for i in 0..self.list.len() {
let j: usize = rng.gen_range(i, self.list.len());
let tmp = self.list[i];
self.list[i] = self.list[j];
self.list[j] = tmp;
}
self.list.clone()
}
}