Codeforces Mahmoud and a Message(水

本文介绍了一道关于最长不同子序列的编程题,通过比较两个字符串并找出它们之间最长的不同子序列。若字符串相同,则输出-1;反之输出两字符串中较长者的长度。

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A. Mahmoud and Longest Uncommon Subsequence

time limit per test
2 seconds
memory limit per test
256 megabytes
input
standard input
output
standard output

While Mahmoud and Ehab were practicing for IOI, they found a problem which name was Longest common subsequence. They solved it, and then Ehab challenged Mahmoud with another problem.

Given two strings a and b, find the length of their longest uncommon subsequence, which is the longest string that is a subsequence of one of them and not a subsequence of the other.

A subsequence of some string is a sequence of characters that appears in the same order in the string, The appearances don’t have to be consecutive, for example, strings “ac“, “bc“, “abc” and “a” are subsequences of string “abc” while strings “abbc” and “acb” are not. The empty string is a subsequence of any string. Any string is a subsequence of itself.

Input

The first line contains string a, and the second line — string b. Both of these strings are non-empty and consist of lowercase letters of English alphabet. The length of each string is not bigger than 105 characters.

Output

If there’s no uncommon subsequence, print “-1“. Otherwise print the length of the longest uncommon subsequence of a and b.

Examples
Input
abcd
defgh
Output
5
Input
a
a
Output
-1
Note

In the first example: you can choose “defgh” from string b as it is the longest subsequence of string b that doesn’t appear as a subsequence of string a.

题意:给两个字符串,如果两个字符串相等就输出-1
反之则输出最大的字符串长度
水题
难点就是英语太差差点看成了动态规划

#include<stdio.h>
#include<string.h>
#include<algorithm>
using namespace std;
#define N 100005
char str1[N], str2[N];
int main()
{
    while(~scanf("%s%s",str1,str2)) {
        int len1 = strlen(str1);
        int len2 = strlen(str2);

        if(strcmp(str1,str2))
            printf("%d\n",max(len1,len2));
        else
            printf("-1\n");
        memset(str1,0,sizeof(str1));
        memset(str2,0,sizeof(str2));
    }
return 0;
}
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