python 对key为时间的dict排序

import time


def date_compare(item1, item2):
    t1 = time.mktime(time.strptime(item1, '%Y/%m/%d'))
    t2 = time.mktime(time.strptime(item2, '%Y/%m/%d'))
    print(t1, t2)
    if t1 < t2:
        return -1
    elif t1 > t2:
        return 1
    else:
        return 0

if __name__ == '__main__':

    d = {'2016/08/17': 'qqq', '2016/08/19': 'qqq',    '2016/08/16': 'qqq',  '2016/11/15': 'qqq', 
    '2016/08/12': 'qqq','2016/08/19': 'qqq'}
    keys = d.keys()
    q = sorted(keys, date_compare)
    print(keys)