[LeetCode26] Remove Duplicates from Sorted Array

作为LeetCode:80的先导题，不会做80的先看这题。

Given a sorted array, remove the duplicates in place such that each element appear only once and return the new length.

Do not allocate extra space for another array, you must do this in place with constant memory.

For example,
Given input array nums = [1,1,2],

Your function should return length = 2, with the first two elements of nums being 1 and 2 respectively. It doesn't matter what you leave beyond the new length.

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C++实现:

从头往后依次比较，遇到不同的就把他放到前面，若要得到最后的数组结果 可以使用 nums.resize(index+1).

class Solution {
public:
    int removeDuplicates(vector<int>& nums) {
        if (nums.size() == 0)
		return 0;
	int index = 0;
	for (int i = 0; i < nums.size(); i++)
	{
		if (nums[index] != nums[i])
			nums[++index] = nums[i];
	}
	return index + 1;
    }
};