Given a binary tree, return the zigzag level order traversal of its nodes' values. (ie, from left to right, then right to left for the next level and alternate between).
For example:
Given binary tree {3,9,20,#,#,15,7},
3
/ \
9 20
/ \
15 7
return its zigzag level order traversal as:
[ [3], [20,9], [15,7] ]
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public ArrayList<ArrayList<Integer>> zigzagLevelOrder(TreeNode root) {
// Start typing your Java solution below
// DO NOT write main() function
ArrayList<ArrayList<Integer>> res = new ArrayList<ArrayList<Integer>>();
ArrayList<Integer> line;
Stack<TreeNode> level = new Stack<TreeNode>();
Stack<TreeNode> next_lev;
if (root == null)
return res;
level.add(root);
boolean flag = false;
while (!level.isEmpty()) {
line = new ArrayList<Integer>();
next_lev = new Stack<TreeNode>();
while(!level.isEmpty()) {
TreeNode cur = level.pop();
line.add(cur.val);
if (flag) {
if (cur.right != null)
next_lev.add(cur.right);
if (cur.left != null)
next_lev.add(cur.left);
} else {
if (cur.left != null)
next_lev.add(cur.left);
if (cur.right != null)
next_lev.add(cur.right);
}
}
res.add(line);
level = next_lev;
flag = !flag;
}
return res;
}
}

本文深入探讨了如何使用Java编程语言实现二叉树的Zigzag层次遍历算法,通过栈数据结构巧妙地解决节点顺序问题,为读者提供了一个清晰的实现步骤和代码示例。
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