You are climbing a stair case. It takes n steps to reach to the top.
Each time you can either climb 1 or 2 steps. In how many distinct ways can you climb to the top?
public class Solution {
public int climbStairs(int n) {
// Start typing your Java solution below
// DO NOT write main() function
if(n == 0)
return 0;
else if(n == 1)
return 1;
else if(n == 2)
return 2;
int pre1 = 1;
int pre2 = 2;
int res = 0;
for(int i = 3; i <= n; i++){
res = pre1 + pre2;
pre1 = pre2;
pre2 = res;
}
return res;
}
}
本文提供了一种使用Java解决爬楼梯问题的方法。该问题要求计算达到楼梯顶部的不同方式的数量,每次可以爬1或2个台阶。通过迭代方法实现,避免了递归带来的效率问题。
483

被折叠的 条评论
为什么被折叠?



