Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1. The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
Pay attention to this one. Passed after several bug fixes.
public class Solution {
public int threeSumClosest(int[] num, int target) {
// Start typing your Java solution below
// DO NOT write main() function
if (num.length < 3)
return 0;
Arrays.sort(num);
int origin, left, right, res = 0, sum, distance = Integer.MAX_VALUE, cur_dis;
for (int i = 0; i < num.length - 2;) {
origin = num[i];
left = i + 1;
right = num.length - 1;
while (left < right) {
sum = origin + num[left] + num[right];
cur_dis = Math.abs(origin + num[left] + num[right] - target);
if(cur_dis < distance){
distance = cur_dis;
res = sum;
}
if (sum == target) {
return res;
} else if (sum >= target) {
--right;
} else {
++left;
}
}
while (++i < num.length && num[i] == origin);
}
return res;
}
}