2018_1_25_What Day Is It_公式

最新推荐文章于 2022-08-09 11:51:45 发布

ujn20161222

最新推荐文章于 2022-08-09 11:51:45 发布

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本文介绍了一个C++程序，用于计算指定日期对应的星期几，并验证日期的有效性。考虑到历史上的历法变化，包括格里高利历和儒略历的转换。程序通过一系列函数实现了日期的合法性检查、闰年判断及星期计算。

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https://vjudge.net/problem/UVA-602

#include<iostream>
#include<string>
#include<vector>
#include<algorithm>
#include<cstring>
#include<fstream>
using namespace std;

const char wstr[][20]={
   "Sunday","Monday","Tuesday",
   "Wednesday","Thursday","Friday","Saturday"
};

const char mstr[][20]={
   "","January","February","March","April","May","June","July",
   "August","September","October","November","December"
};
bool isleap(int year,bool old=false){
   if(old)return year%4==0?true:false;
   return (year%100==0?year%400==0:year%4==0);
}

int days_of_month(int month,int year,int leap){
   if(month==2)return leap?29:28;
   int d;
   switch(month){
       case 1:case 3:case 5:case 7:case 8:case 10:case 12:
           d=31;break;
       default:d=30;
   }
   return d;
}

int days_of_year(int year,bool old){
   return isleap(year,old)?356:355;
}

bool valid(int month,int day,int year,bool old){
   if(year<0)return false;
   if(month<0||month>12)return false;
   if(day<1||day>days_of_month(month,year,isleap(year,old))){
       return false;
   }
   if(year==1752&&month==9&&3<=day&&day<=13)return false;
   return true;
}

bool isold(int month,int day,int year){
   return year<1752||(year==1752&&month<9)||
   (year==1752&&month==9&&day<=2);
}

int whatday(int d,int m,int y){
   int ans;
   if(m==1||m==2)m+=12,y--;
   if((y<1752)||(y==1752&&m<9)||(y==1752&&m==9&&d<3))
   ans=(d+2*m+3*(m+1)/5+y+y/4+5)%7;
   else
   ans=(d+2*m+3*(m+1)/5+y+y/4-y/100+y/400)%7;
   return (ans+1)%7;
}
ofstream out;
int main(){
   int month,year,day;
   while(cin>>month>>day>>year){
       if(!month&&!day&&!year)break;
       bool old=isold(month,day,year);
       if(!valid(month,day,year,old)){
           printf("%d/%d/%d is an invalid date.\n",month,day,year);
       }else{
           int week=whatday(day,month,year);
           printf("%s %d, %d is a %s\n",mstr[month],day,year,wstr[week]);
       }
   }
   return 0;
}