问题描述:
Write an algorithm to determine if a number is "happy".
A happy number is a number defined by the following process: Starting with any positive integer, replace the number by the sum of the squares of its digits, and repeat the process until the number equals 1 (where it will stay), or it loops endlessly in a cycle which does not include 1. Those numbers for which this process ends in 1 are happy numbers.
Example: 19 is a happy number
- 12 + 92 = 82
- 82 + 22 = 68
- 62 + 82 = 100
- 12 + 02 + 02 = 1
思路:
设置一个set存储已经出现过的数字,防止出现死循环,处理数字的函数按照规则进行,将数字的每个位置都进行平方而后相加即可。
java代码:
public class Solution {
public boolean isHappy(int n) {
if(n < 1) return false;
if(n == 1) return true;
Set<Long> set = new HashSet<Long>();
long ln = n;
while(ln <= Integer.MAX_VALUE){
if(set.contains(ln)) return false;
else set.add(ln);
ln = digitSquare(ln);
if(ln == 1) return true;
}
return false;
}
private long digitSquare(long ln) {
long sum = 0;
while(ln != 0) {
sum += Math.pow(ln % 10, 2);
ln /= 10;
}
return sum;
}
}