1. 写一个程序，实现按照顺序输出数字

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于 2020-12-10 14:45:28 首次发布

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本文通过两个Go语言示例展示了如何使用通道实现任务间的同步与通信。第一个案例涉及多个goroutine通过整数通道协作打印数字；第二个案例则展示了三个goroutine如何通过布尔通道轮流打印数字1、2、3。这些示例有助于理解Go语言中并发与通道的基本用法。

package main

import (
    "fmt"
    "time"
)

func printNumber(chanIn chan int, chanOut chan int, number int, count int) {
    for i := 0; i < count; i++ {
       <-chanIn
       fmt.Print(number)
       chanOut <- 1
    }
}

func main() {
    n := 10

    channels := make([]chan int, n)

    for i := 0; i < n; i++ {
       channels[i] = make(chan int)
    }

    for i := 0; i < n; i++ {
       if i == n-1 {
          // 最后
          go printNumber(channels[n-1], channels[0], i+1, n)
       } else {
          go printNumber(channels[i], channels[i+1], i+1, n)
       }
    }

    channels[0] <- 1

    time.Sleep(10 * time.Second)
}

package main

import "time"

func printNumber01(chan01 chan bool, chan02 chan bool, count int) {
    for i := 0; i < count; i++ {
       <-chan01
       print("1")
       chan02 <- true
    }
}
func printNumber02(chan02 chan bool, chan03 chan bool, count int) {
    for i := 0; i < count; i++ {
       <-chan02
       print("2")
       chan03 <- true
    }
}

func printNumber03(chan03 chan bool, chan01 chan bool, count int) {
    for i := 0; i < count; i++ {
       <-chan03
       print("3")
       chan01 <- true
    }
}

func main() {
    var chan01, chan02, chan03 = make(chan bool), make(chan bool), make(chan bool)

    go printNumber01(chan01, chan02, 3)
    go printNumber02(chan02, chan03, 3)
    go printNumber03(chan03, chan01, 3)
    chan01 <- true

    time.Sleep(12 * time.Second)
}