北邮新OJ87

题目链接

#include<iostream>
#include<stdio.h>
#include<stdlib.h>
#include<string>
#include<sstream>
using namespace std;
int C(int y,int m,int d)
{
    int sum=0;
    if(m==1)
        sum=d;
    else if(m==2)
        sum=31+d;
    else if(m==3)
        sum=59+d;
    else if(m==4)
        sum=90+d;
    else if(m==5)
        sum=120+d;
    else if(m==6)
        sum=151+d;
    else if(m==7)
        sum=181+d;
    else if(m==8)
        sum=212+d;
    else if(m==9)
        sum=243+d;
    else if(m==10)
        sum=273+d;
    else if(m==11)
        sum=304+d;
    else if(m==12)
        sum=334+d;
    else
        ;
    if(y%100==0&&y%400==0&&m>=3)
        sum++;
    else if(y%100!=0&&y%4==0&&m>=3)
        sum++;
    else
        ;
    return sum;
}
int main()
{
    int m;
    while(scanf("%d",&m)!=EOF)
    {
        getchar();
        for(int k=1;k<=m;k++)
        {
            string s;
            int index1=0;
            int index2=0;
            getline(cin,s);
            for(int i=0;i<s.length();i++)
            {
                if(index1!=0&&s[i]==':')
                    index2=i;
                if(index1==0&&s[i]==':')
                    index1=i;
            }
            stringstream s1,s2,s3;
            int y,m,d;
            string ss1,ss2,ss3;
            ss1=s.substr(0,index1);
            ss3=s.substr(index2+1,s.length()-index2-1);
            ss2=s.substr(index1+1,s.length()-ss1.length()-ss3.length()-2);
            s1<<ss1;
            s2<<ss2;
            s3<<ss3;
            s1>>y;
            s2>>m;
            s3>>d;
            printf("%d\n",C(y,m,d));
        }
    }
}