71. Simplify Path-优快云博客

本文介绍了一个C++实现的算法，用于简化Unix风格的文件路径。该算法通过栈来处理路径中的'..'和'.'，去除多余的斜杠，并返回规范化的路径。文章详细解释了如何处理各种特殊情况。

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Given an absolute path for a file (Unix-style), simplify it.

For example,
path = "/home/", => "/home"

path = "/a/./b/../../c/", => "/c"

Corner Cases:

Did you consider the case where path = "/../"?
In this case, you should return "/".
Another corner case is the path might contain multiple slashes '/' together, such as "/home//foo/".
In this case, you should ignore redundant slashes and return "/home/foo".

class Solution {
public:
    string simplifyPath(string path) {
        string res = "";
        stack<string> st;
        int start = 0;
        while (start < path.size()) {
            while (start < path.size() && path[start] == '/') {
                start++;
            }
            int end = start;
            while (end < path.size() && path[end] != '/') {
                end++;
            }
            string tmp = path.substr(start, end - start);
            start = end + 1;
            if (tmp == ".." && st.empty()) {
                continue;
            }
            else if (tmp == ".." && !st.empty()) {
                st.pop();
            }
            else if (tmp == "." || tmp == "") {
                continue;
            }
            else {
                st.push(tmp);
            }
        }
        if (st.empty()) {
            return "/";
        }
        while (!st.empty()) {
            res = "/" + st.top() + res;
            st.pop();
        }
        return res;
    }
};

注意当str为空的时候，不要加入stack里面，一开始我犯错误了