一个关于计算出日期差距的函数

最新推荐文章于 2024-02-03 20:43:32 发布

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最新推荐文章于 2024-02-03 20:43:32 发布

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分类专栏：学习积累文章标签： string 日期转化

本文链接：https://blog.youkuaiyun.com/gamer1028/article/details/26732289

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<pre name="code" class="cpp">//参数nYear，nMonth，nDay 表示当天日期，nBeforeToday 表示几天前

void transferToActualDay( int &nYear,int &nMonth,int &nDay,int nBeforeToday )
{
    if (nDay <= nBeforeToday)
    {
        nBeforeToday -= nDay;


        switch(nMonth)
        {
        case 1:
            {
                nYear --;
                nMonth = 12;
                nDay = 31;
            }
            break;
        case 2:
            {
                nMonth --;
                nDay = 31;
            }
            break;
        case 3:
            {
                nMonth --;
                if((nYear%4==0&&nYear%100!=0)||(nYear%400==0))
                {
                    nDay = 29;
                }
                else
                {
                    nDay = 28;
                }
            }
            break;
        case 4:
        case 6:
        case 9:
        case 11:
            {
                nMonth --;
                nDay = 31;
            }
            break;
        case 5:
        case 7:
        case 8:
        case 10:
        case 12:
            {
                nMonth --;
                nDay = 30;
            }
            break;
        default:
            break;
        }

        transferToActualDay(nYear,nMonth,nDay,nBeforeToday);
    }
    else
    {
        nDay -= nBeforeToday;
    }
}