C/C++ 浮点数转化为 2,8,10,16 进制的数

#include<iostream.h>
#include<math.h>


void f1(int m, int n) { //转整数部分
 if(m) { f1(m/n,n);
      if(n<10) cout<<m%n;
      else m%n>=10? cout<<char(m%n-10+'A') : cout<<m%n;
 }
}


void f2(double m, int n) { //转小数部分
 while(m) { if(n<10) cout<<int(m*n);
            else m*n>=10? cout<<char(int(m*n)-10+'A') : cout<<int(m*n);
      m = m*n - int(m*n);
 }
}


void f(double m, int n) {
 f1(m, n);
 if(int(m) == m) return;
 cout<<'.';
 m -= int(m);
 f2(m, n);
}


void f10(char c[], double m) {
 cout<<' '<<c<<" 转换成"<< 2<<"进制 = "; f(m, 2); cout<<endl;
 cout<<' '<<c<<" 转换成"<< 8<<"进制 = "; f(m, 8); cout<<endl;
 cout<<' '<<c<<" 转换成"<<16<<"进制 = "; f(m,16); cout<&