题目要求:Supposethat a website contains two tables, the Customers table and the Orders table.Write a SQL query to find all customers who never order anything.
解答:1)LEFT JOIN 左联结:
SELECT NameAS Customers
FROM Customers LEFT JOIN Orders
ON Customers.Id = Orders.CustomerId
WHERE Orders.Id IS NULL
2) 组合查询,使用 NOT IN:
SELECT Name AS Customers
FROM Customers WHERE Id NOT IN
(SELECT CustomerId FROM Orders)
3) 而EXISTS 与 IN最大的区别在于 IN 引导的子句只能返回一个字段,比如:
select name from student where sex = 'm' and mark in (select 1,2,3from grade where ...)
in子句返回了三个字段,这是不正确的,exists子句是允许的,但in只允许有一个字段返回,在1,2,3中随便去了两个字段即可。
解法:
SELECT Name AS Customers
FROM Customers WHERE NOT EXISTS
(SELECT * FROM Orders
WHERE Orders.CustomerId = Customers.Id)