/*
sum[rt]表示这个区间内最大的连续区间长度
lsum[rt]表示这个区间左边缘最大的连续区间长度,rsum同理。
然后对于一个端点的意义,表示的是到下一个端点间的这个长度是否被占用
剩下的就是一般的线段树方法了
*/
#define _CRT_SECURE_NO_WARNINGS
#include<iostream>
#include<algorithm>
#include<cstdio>
#include<cstring>
using namespace std;
#define MAX 50005
#define ls rt<<1
#define rs ls|1
#define m ((l+r)>>1)
int sum[MAX << 2], lsum[MAX << 2], rsum[MAX << 2],col[MAX<<2];
void uprt(int l, int r, int rt)
{
int rlen = (r-l+1)>>1;
int llen = r - l + 1 - rlen;
lsum[rt] = lsum[ls];
rsum[rt] = rsum[rs];
if (lsum[rt] == llen)
lsum[rt] += lsum[rs];
if (rsum[rt] == rlen)
rsum[rt] += rsum[ls];
sum[rt] = max(rsum[ls] + lsum[rs], max(sum[ls], sum[rs]));
}
void ups(int l, int r, int rt)
{
int rlen = (r - l + 1) >> 1;
int llen = r - l + 1 - rlen;
if (col[rt] == 0)
sum[ls] = sum[rs] = 0;
else
if (col[rt] == 1)
{
sum[ls] = llen;
sum[rs] = rlen;
}
if (col[rt] != -1)
{
rsum[ls] = lsum[ls] = sum[ls];
lsum[rs] = rsum[rs] = sum[rs];
col[ls] = col[rs] = col[rt];
col[rt] = -1;
}
}
void build(int l, int r, int rt)
{
lsum[rt] = rsum[rt] = sum[rt] = r - l + 1;
if (l == r)
return;
int mid = m;
build(l, mid, ls);
build(mid + 1, r, rs);
}
int query(int len, int l, int r, int rt)
{
if (l == r)return l;
ups(l, r, rt);
int mid = m;
if (sum[ls] >= len)return query(len, l, mid, ls);
if (rsum[ls] + lsum[rs] >= len&&rsum[ls]!=0) return mid - rsum[ls] + 1;
return query(len, mid + 1, r, rs);
}
void updata(int L, int R, int c, int l, int r, int rt)
{
if (L <= l&&r <= R)
{
col[rt] = c;
if (c == 1)
sum[rt] = r - l + 1;
else
if (c == 0)
sum[rt] = 0;
lsum[rt] = rsum[rt] = sum[rt];
return;
}
ups(l, r, rt);
int mid = m;
if (L <= mid)
updata(L, R, c, l, mid, ls);
if (R > mid)
updata(L, R, c, mid + 1, r, rs);
uprt(l, r, rt);
}
int main()
{
int n, k;
while (~scanf("%d%d", &n, &k))
{
memset(col, -1, sizeof(col));
build(1, n, 1);
int a, b, c;
int cur;
while (k--)
{
scanf("%d", &a);
if (a == 1)
{
scanf("%d", &b);
if (sum[1] < b)
cur = 0;
else
{
cur = query(b, 1, n, 1);
updata(cur, cur + b - 1, 0, 1, n, 1);
}
printf("%d\n", cur);
}
else
{
scanf("%d%d", &b, &c);
updata(b, b + c - 1, 1, 1, n, 1);
}
}
}
}