
杭电acm
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A+B for Input-Output Practice (V)
#include int main(){int a,k,n,i,j,s;scanf("%d",&n);for(j=0;j {while(scanf("%d",&k)!=EOF){s=0;for(i=0;i {scanf("%d",&a);s=s+a;} printf("%d\n",s);}}retur原创 2014-01-25 16:26:29 · 371 阅读 · 0 评论 -
A+B for Input-Output Practice (I)
#include int main(){int a,b,s;while (scanf("%d%d",&a,&b)!=EOF){s=a+b;printf("%d\n",s);}return 1;}心得:此代码不是你输入了2个数它直接输出和就可以啦。它得要你只要输入了2个数,它就必须输出和。这时,不能马上结束,那么我就想到了ctrl+z作为结束。原创 2014-01-25 11:21:32 · 472 阅读 · 0 评论 -
A+B for Input-Output Practice (II)
#include int main(){int a,b,k,i,s;scanf("%d",&k);for(i=0;i{scanf("%d%d",&a,&b);s=a+b;printf("%d\n",s);}return 1;}这道题跟上道稍微有些不一样,它需要你在最前方输入一个总数,而不是一直作和下去。这样就需要用到循环。原创 2014-01-25 11:30:08 · 403 阅读 · 0 评论 -
A+B for Input-Output Practice (VI)
#include int main(){int a,k,i,s; {while(scanf("%d",&k)!=EOF){s=0;for(i=0;i {scanf("%d",&a);s=s+a;} printf("%d\n",s);}}return 1;}不用讲,这道题简单的想死,前面的稍微删一删原创 2014-01-25 16:34:49 · 529 阅读 · 0 评论 -
A+B for Input-Output Practice (IV)
#include int main(){int a,k,i,s; scanf("%d",&k);while(k!=0){s=0;for(i=0;i {scanf("%d",&a);s=s+a;} if(k==0)break; printf("%d\n",s);scanf("%d",&k);}return 1;原创 2014-01-25 16:12:03 · 484 阅读 · 0 评论 -
A+B for Input-Output Practice (III)
#include int main(){int a,b,s;while(s!=0){scanf("%d%d",&a,&b);s=a+b;if(s==0)break;printf("%d\n",s);}return 1;}这道题得以0+0=0作为结束。我没有做过此类题目。一开始我没有if和break,还用了while(a!=0&&b!=0),结果是原创 2014-01-25 13:38:56 · 435 阅读 · 0 评论 -
A+B for Input-Output Practice (VII)
#include int main(){int a,b,s; while(scanf("%d%d",&a,&b)!=EOF){s=a+b; printf("%d\n",s);printf("\n");}return 1;}这题只是多了一个换一行再输出。原创 2014-01-25 16:42:12 · 378 阅读 · 0 评论 -
A+B for Input-Output Practice (VIII)
#include int main(){int a,n,k,i,j,s;scanf("%d",&k); for(i=0;i{scanf("%d",&n); s=0;for(j=0;j{scanf("%d",&a);s=s+a;} printf("%d\n",s);if(i==(k-1))break;printf原创 2014-01-25 20:29:10 · 2602 阅读 · 0 评论