/*
扫描线求矩阵的覆盖面
离散化
线段树求面积并升级版
*/
#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
#define lson (pos<<1)
#define rson (pos<<1|1)
typedef long long LL;
const int maxn = 10005;
int cnt,ret;
struct Seg{
double a,b,h;
int c;
Seg(double a = 0,double b = 0,double h = 0,int c = 0):
a(a),b(b),h(h),c(c){};
friend bool operator < (Seg p,Seg q){
return p.h < q.h;
}
}seg[maxn];
double Hash[maxn];
int HASH(double t){
return lower_bound(Hash,Hash + ret,t) - Hash;
}
void Hash_init(){
sort(Hash,Hash + ret);
ret = unique(Hash,Hash + ret) - Hash;
}
struct Node{
int l,r,col;
double s,ss;
int mid(){
return (l + r) >> 1;
}
double len(){
return Hash[r + 1] - Hash[l];
}
}node[maxn << 2];
void build(int l,int r,int pos){
node[pos].l = l;
node[pos].r = r;
node[pos].col = 0;
node[pos].ss = node[pos].s = 0;
if(l == r) return;
int mid = node[pos].mid();
build(l,mid,lson);
build(mid + 1,r,rson);
}
void pushup(int pos){
if(node[pos].col){
node[pos].s = node[pos].len();
}
else if(node[pos]. l == node[pos].r){
node[pos].s = 0;
}
else{
node[pos].s = node[lson].s + node[rson].s;
}
if(node[pos].col > 1){
node[pos].ss = node[pos].len();
}
else if(node[pos].l == node[pos].r){
node[pos].ss = 0;
}
else if(node[pos].col == 1){
node[pos].ss = node[lson].s + node[rson].s;
}
else{
node[pos].ss = node[lson].ss + node[rson].ss;
}
}
void update(int l,int r,int pos,int d){
if(l <= node[pos].l && node[pos].r <= r){
node[pos].col += d;
pushup(pos);
return;
}
int mid = node[pos].mid();
if(l <= mid)
update(l,r,lson,d);
if(r > mid)
update(l,r,rson,d);
pushup(pos);
}
int main(){
int T,n;
scanf("%d",&T);
while(T--){
scanf("%d",&n);
cnt = 0;
ret = 0;
double a,b,c,d;
for(int i = 0; i < n; i++){
scanf("%lf%lf%lf%lf",&a,&b,&c,&d);
seg[cnt++] = Seg(a,c,b,1);
seg[cnt++] = Seg(a,c,d,-1);
Hash[ret++] = a;
Hash[ret++] = c;
}
Hash_init();
sort(seg,seg + cnt);
build(0,ret,1);
double ans = 0;
for(int i = 0; i < cnt - 1; i++){
int l = HASH(seg[i].a),r = HASH(seg[i].b) - 1,c = seg[i].c;
update(l,r,1,c);
ans += node[1].ss * (seg[i + 1].h - seg[i].h);
}
printf("%.2f\n",ans);
}
return 0;
}
/*
1
2
0 0 1 1
0 0 1 1
*/
HDU 1255
最新推荐文章于 2021-01-19 17:58:25 发布