题目链接:Robots
旋转45度坐标系,x’=x+y,y’=x-y,然后横纵坐标变成独立问题,接下来dp。
#include <bits/stdc++.h>
using namespace std ;
typedef long long LL ;
#define clr( a , x ) memset ( a , x , sizeof a )
const int MAXN = 205 ;
const int MAXM = 2005 ;
const int mod = 1e9 + 7 ;
int n , m , k ;
int L[MAXN] , R[MAXN] ;
int X[MAXN] , Y[MAXN] ;
int f[MAXM] , vf[MAXM] ;
int a[21][2] , b[21][21] ;
int dp[21][MAXM][2] ;
int tmp[MAXM][2] ;
int powmod ( int x , int n ) {
int r = 1 ;
while ( n ) {
if ( n & 1 ) r = ( LL ) r * x % mod ;
x = ( LL ) x * x % mod ;
n >>= 1 ;
}
return r ;
}
int c ( int x , int y ) {
if ( x < y ) return 0 ;
return ( LL ) f[x] * vf[y] % mod * vf[x - y] % mod ;
}
void mul ( int& x , int y ) {
x = ( LL ) x * y % mod ;
}
void up ( int& x , int y ) {
x += y ;
if ( x >= mod ) x -= mod ;
}
void solve () {
scanf ( "%d%d%d" , &n , &m , &k ) ;
int l = 0 ;
for ( int i = 1 ; i <= m ; ++ i ) {
int x ;
scanf ( "%d" , &x ) ;
L[i] = l + 1 ;
R[i] = l + x ;
l += x ;
}
for ( int i = 1 ; i <= n ; ++ i ) {
int x , y ;
scanf ( "%d%d" , &x , &y ) ;
X[i] = x + y + 1000 ;
Y[i] = x - y + 1000 ;
}
for ( int i = 1 ; i <= m ; ++ i ) {
for ( int j = 0 ; j < MAXM ; ++ j ) {
dp[i][j][0] = dp[i][j][1] = 1 ;
}
}
int o = 1 ;
for ( int i = 1 ; i <= n ; ++ i ) {
if ( i > R[o] ) ++ o ;
for ( int j = 0 ; j < MAXM ; ++ j ) {
int t = abs ( X[i] - j ) ;
if ( t % 2 != k % 2 || t > k ) dp[o][j][0] = 0 ;
else mul ( dp[o][j][0] , c ( k , ( k + t ) / 2 ) ) ;
t = abs ( Y[i] - j ) ;
if ( t % 2 != k % 2 || t > k ) dp[o][j][1] = 0 ;
else mul ( dp[o][j][1] , c ( k , ( k + t ) / 2 ) ) ;
}
}
for ( int i = 1 ; i <= m ; ++ i ) {
for ( int k = 0 ; k < MAXM ; ++ k ) {
tmp[k][0] = tmp[k][1] = 1 ;
}
for ( int j = i ; j <= m ; ++ j ) {
int x = 0 , y = 0 ;
for ( int k = 0 ; k < MAXM ; ++ k ) {
mul ( tmp[k][0] , dp[j][k][0] ) ;
mul ( tmp[k][1] , dp[j][k][1] ) ;
up ( x , tmp[k][0] ) ;
up ( y , tmp[k][1] ) ;
}
b[i][j] = ( LL ) x * y % mod ;
}
}
clr ( a , 0 ) ;
a[0][0] = 1 ;
for ( int i = 1 ; i <= m ; ++ i ) {
for ( int j = 1 ; j <= i ; ++ j ) {
int t = ( j - 1 ) & 1 ;
up ( a[i][0] , ( LL ) a[i - j][0 ^ t] * b[i - j + 1][i] % mod ) ;
up ( a[i][1] , ( LL ) a[i - j][1 ^ t] * b[i - j + 1][i] % mod ) ;
}
}
printf ( "%d\n" , ( a[m][0] - a[m][1] + mod ) % mod ) ;
}
int main () {
int T ;
f[0] = vf[0] = 1 ;
for ( int i = 1 ; i < MAXM ; ++ i ) {
f[i] = ( LL ) f[i - 1] * i % mod ;
vf[i] = powmod ( f[i] , mod - 2 ) ;
}
scanf ( "%d" , &T ) ;
for ( int i = 1 ; i <= T ; ++ i ) {
printf ( "Case #%d: " , i ) ;
solve () ;
}
return 0 ;
}