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最新推荐文章于 2022-12-02 20:39:05 发布

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#ACM #UVA 10071

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本文提供了一种快速计算粒子在双倍时间内的位移的方法，适用于初速度和恒定加速度的粒子运动场景。通过简单的数学公式，我们可以轻松找到答案。

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Input: standard input

Output: standard output

A particle has initial velocity and constant acceleration. If its velocity after certain time is v then what will its displacement be in twice of that time?

Input

The input will contain two integers in each line. Each line makes one set of input. These two integers denote the value of v (-100 <= v <= 100) and t(0<=t<= 200) ( t means at the time the particle gains that velocity)

Output

For each line of input print a single integer in one line denoting the displacement in double of that time.

Sample Input

0 0
5 12

Sample Output

0
120

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解题报告

#include<stdio.h> 
int main() 
{ 
    int v,t,s; 
    while(scanf("%d %d",&v,&t)!=EOF) 
    { 
        printf("%d\n",v*t*2); 
    } 
    return 0; 
}