UVA 10474 - Where is the Marble?

最新推荐文章于 2022-01-18 15:51:31 发布

原创最新推荐文章于 2022-01-18 15:51:31 发布 · 1.4k 阅读

0 ·

CC 4.0 BY-SA版权

文章标签：

#二分查找求下界 #uva #acm #c++

基础算法同时被 2 个专栏收录

17 篇文章

订阅专栏

水题

15 篇文章

订阅专栏

本文深入探讨了游戏开发领域的关键技术，包括游戏引擎、编程语言、硬件优化等，并重点阐述了AI音视频处理的应用场景和实现方法，如语义识别、语音识别、AR增强现实等。通过实例分析，揭示了技术融合带来的创新解决方案。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

10474 - Where is the Marble?

Time limit: 3.000 seconds

Where is the Marble?

Raju and Meena love to play with Marbles. They have got a lot of marbles with numbers written on them. At the beginning, Raju would place the marbles one after another in ascending order of the numbers written on them. Then Meena would ask Raju to find the first marble with a certain number. She would count 1...2...3. Raju gets one point for correct answer, and Meena gets the point if Raju fails. After some fixed number of trials the game ends and the player with maximum points wins. Today it's your chance to play as Raju. Being the smart kid, you'd be taking the favor of a computer. But don't underestimate Meena, she had written a program to keep track how much time you're taking to give all the answers. So now you have to write a program, which will help you in your role as Raju.

Input

There can be multiple test cases. Total no of test cases is less than 65. Each test case consists begins with 2 integers: N the number of marbles and Q the number of queries Mina would make. The next N lines would contain the numbers written on the N marbles. These marble numbers will not come in any particular order. Following Q lines will have Q queries. Be assured, none of the input numbers are greater than 10000 and none of them are negative.

Input is terminated by a test case where N = 0 and Q = 0.

Output

For each test case output the serial number of the case.

For each of the queries, print one line of output. The format of this line will depend upon whether or not the query number is written upon any of the marbles. The two different formats are described below:

`x found at y', if the first marble with number x was found at position y. Positions are numbered 1, 2,..., N.
`x not found', if the marble with number x is not present.

Look at the output for sample input for details.

Sample Input

Sample Output

CASE# 1:
5 found at 4
CASE# 2:
2 not found
3 found at 3

Problem-setter: Monirul Hasan Tomal, Southeast University

#include <stdio.h>
#include <stdlib.h>
#include <algorithm>
#define max 10001
int a[max],b[max];
void search(int num,int N)
{
    int low=1,high=N,mid;
    int ok=0;
    mid=(low+high)/2;
    while(low<high)
    {
        if(a[mid]<num)low=mid+1;
        if(a[mid]>num)high=mid;
        mid=(low+high)/2;
        if(a[mid]==num){while(a[--mid]==num);ok=mid+1;break;}
    }
    if(ok)printf("%d found at %d\n",num,ok);
    else printf("%d not found\n",num);
}
int main()
{
    int N,Q;
    int count=1;
    freopen("input.txt","r",stdin);
    while(~scanf("%d%d",&N,&Q)&&(Q||N))
    {
        for(int i=1;i<=N;i++){
            scanf("%d",a+i);
        }
        std::sort(a+1,a+1+N);
        printf("CASE# %d:\n",count);
        count++;
        for(int i=1;i<=Q;i++){
            scanf("%d",b+i);
            search(b[i],N);
        }
    }
    return 0;
}