在多线程环境下,使用延迟加载的方式实现单例模式,会出现错误。
例如,使用如下方式实现单例类:
package study20170307;
/**
* Created by apple on 17/3/7.
*/
public class SingleJavaTest {
private static SingleJavaTest singleJavaTest = null;
public static SingleJavaTest getSingleJavaTest(){
if (singleJavaTest == null){
//模拟在创建对象之前做一些准备工作
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
singleJavaTest = new SingleJavaTest();
}
return singleJavaTest;
}
}
创建线程类:
package study20170307;
import java.io.*;
/**
* Created by apple on 17/3/7.
*/
public class ThreadA extends Thread {
@Override
public void run() {
super.run();
System.out.println(SingleJavaTest.getSingleJavaTest().hashCode());
}
}
创建运行类:
package study20170307;
import java.io.IOException;
import java.io.PipedInputStream;
import java.io.PipedOutputStream;
import java.util.concurrent.locks.ReentrantLock;
/**
* Created by apple on 17/3/7.
*/
public class Main {
public static void main(String[] args) {
ThreadA thread1 = new ThreadA();
ThreadA thread2 = new ThreadA();
ThreadA thread3 = new ThreadA();
thread1.start();
thread2.start();
thread3.start();
}
}
运行效果如图所示:
说明单例类并没有实现成功。
那么如何对上述单例类进行修改呢,我们可以将单例类中对象创建的部分放在同步块中,同时还要采用双重判定的方式。此时单例类代码如下:
package study20170307;
/**
* Created by apple on 17/3/7.
*/
public class SingleJavaTest {
private static SingleJavaTest singleJavaTest = null;
public static SingleJavaTest getSingleJavaTest(){
if (singleJavaTest == null){
//模拟在创建对象之前做一些准备工作
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
}
synchronized (SingleJavaTest.class){
if (singleJavaTest == null)singleJavaTest = new SingleJavaTest();
}
}
return singleJavaTest;
}
}
这时运行效果如图所示:
说明单例类成功。