杭电Sum Problem（Java版）解题

最新推荐文章于 2024-08-03 14:51:53 发布

晨_暮

最新推荐文章于 2024-08-03 14:51:53 发布

阅读量632

点赞数 1

CC 4.0 BY-SA版权

分类专栏： java初学文章标签：杭电 ACM

本文链接：https://blog.youkuaiyun.com/u012999325/article/details/81139985

java初学专栏收录该内容

7 篇文章

订阅专栏

本文介绍了一个简单的编程挑战——求和问题(SUMProblem)，该问题要求计算从1到n的所有整数之和。文章提供了Java实现示例，通过读取输入并使用循环结构来计算结果。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

Sum Problem
Time Limit: 1000/500 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 555804    Accepted Submission(s): 140813


Problem Description
Hey, welcome to HDOJ(Hangzhou Dianzi University Online Judge).

In this problem, your task is to calculate SUM(n) = 1 + 2 + 3 + ... + n.
 

Input
The input will consist of a series of integers n, one integer per line.
 

Output
For each case, output SUM(n) in one line, followed by a blank line. You may assume the result will be in the range of 32-bit signed integer.
 

Sample Input
1
100
 

Sample Output
1

5050
 

Author
DOOM III

发现一个特坑爹的，只能用主函数，不能进行自定义方法的调用

import java.util.Scanner;

public class Main {

	public static void main(String[] args) {
	Scanner input =new Scanner(System.in);
	while(input.hasNext()) {
		int a=input.nextInt();
		int c=0;
		for(int i=0;i<(a+1);i++) {
			c+=i;
		}
		System.out.println(c);
        System.out.println("");
		
	}
		

	}
}