object MergedSort {
def main(args: Array[String]) {
def mergeSort[T] (less: (T, T) => Boolean) (input: List[T]): List[T] ={
/**
* @param xList 要合并的有序序列
* @param yList 要和并的有序序列
* @return 合并后的序列
*/
def merge(xList: List[T], yList: List[T]): List[T] =
(xList, yList) match {
case (Nil, _) => yList
case (_, Nil) => xList
case (x :: xtail, y :: ytail) =>
if (less(x, y)) x :: merge(xtail, yList)
else y :: merge(xList, ytail)
}
val n = input.length / 2
if (n == 0) input
else {
val (x, y) = input splitAt n //把要排序的input均分成两个列表
merge(mergeSort(less)(x), mergeSort(less)(y)) //先对分后的两个列表进行归并排序,在对排序好的有序列表进行归并
}
println(mergeSort((x: Int, y: Int) => x < y)(List(3, 7, 9, 5)))
val reversed_mergedsort = mergeSort((x: Int, y: Int) => x > y) _
println(reversed_mergedsort(List(3,7,9,5)))
}
}
}
scala实现归并排序
最新推荐文章于 2021-03-15 18:55:26 发布