leetcode: 717. 1-bit and 2-bit Characters

本文探讨了如何判断给定的比特串是否以一比特特殊字符结尾。通过解析输入比特串,文章提供了一种有效的方法来确定最后一个字符是否为一比特字符。此问题源于两特殊字符的编码方式:一个由单一比特'0'表示,另一个则由两个比特'10'或'11'组成。

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题目:

We have two special characters. The first character can be represented by one bit 0. The second character can be represented by two bits (10 or 11).

Now given a string represented by several bits. Return whether the last character must be a one-bit character or not. The given string will always end with a zero.

Example 1:

Input: 
bits = [1, 0, 0]
Output: True
Explanation: 
The only way to decode it is two-bit character and one-bit character. So the last character is one-bit character.

 

Example 2:

Input: 
bits = [1, 1, 1, 0]
Output: False
Explanation: 
The only way to decode it is two-bit character and two-bit character. So the last character is NOT one-bit character.

 

Note:

  • 1 <= len(bits) <= 1000.
  • bits[i] is always 0 or 1.

C++代码:

class Solution {
public:
    bool isOneBitCharacter(vector<int>& bits) {
        for(int i=0;i<bits.size();i++){
            if(i == bits.size()-1) return true;
            if(bits[i]==1){
                i++;
            }
        }
        return false;
    }
};

 

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