Java多线程实战：同步输出数字与字母-优快云博客

本文通过两个实例介绍Java多线程的使用。第一个实例中，两个线程交替输出数字1-52和字母A-Z，保持12A 34B...的格式。第二个实例涉及三个线程按顺序打印递增数字1-75，形成1,2,3,4,5-6,7,8,9,10-11,12,...75的序列。" 5482215,696402,使用JavaScript控制windowMediaPlayer播放音乐,"['javascript', 'HTML', '媒体播放', '脚本']

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1、创建两个线程，其中一个输出1-52，另外一个输出A-Z。输出格式要求：12A 34B 56C 78D

public class Problem01 {
	public static void main(String[] args) {
		Object object = new Object();
		new Thread(new Number(object)).start();
		;
		new Thread(new Character(object)).start();
		;
	}
}

class Number implements Runnable {

	private Object object;

	public Number(Object object) {
		this.object = object;
	}

	@Override
	public void run() {
		synchronized (object) {
			for (int i = 1; i < 53; i++) {
				if (i > 1 && i % 2 == 1) {
					System.out.print(" ");
				}
				System.out.print(i);
				if (i % 2 == 0) {
					// 先释放锁,唤醒其他线程,再使本线程阻塞
					object.notifyAll();
					try {
						object.wait();
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
			}
		}
	}
}

class Character implements Runnable {

	private Object object;

	public Character(Object object) {
		this.object = object;
	}

	@Override
	public void run() {
		synchronized (object) {
			for (char i = 'A'; i <= 'Z'; i++) {
				System.out.print(i);
				// 先释放锁,唤醒其他线程,再使本线程阻塞
				object.notifyAll();
				if (i < 'Z') {  // 线程执行的最后一次不能堵塞，不然会一直堵塞下去。
					try {
						object.wait();
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
			}
		}
	}
}

2、启动3个线程打印递增的数字, 线程1先打印1,2,3,4,5 然后是线程2打印6,7,8,9,10 然后是线程3打印11,12,13,14,15.接着再由线程1打印16,17,18,19,20....以此类推, 直到打印到75。

public class Problem02 {

	public static void main(String[] args) {
		final Hander hander = new Hander();

		for (int i = 0; i < 3; i++) {
			new Thread(new Runnable() {
				@Override
				public void run() {
					for(int j=0;j<5;j++) {
						hander.print(Thread.currentThread().getName());
					}
				}
			}, i + "").start();
		}
	}
}

class Hander {

	private int no = 1;
	
	private int status = 0;
	
	// 将该方法上锁
	public synchronized void print(String threadName) {
		int threadIndex = Integer.parseInt(threadName);
		while (threadIndex != status) {
			try {
				this.wait();
			} catch (InterruptedException e) {
				e.printStackTrace();
			}
		}
		System.out.print("Thread-"+threadName+" : ");
		for (int count = 0; count < 5; count++, no++) {
			if (count > 0) {
				System.out.print(",");
			}
			System.out.print(no);
		}
		System.out.println();
		status = (status + 1) % 3;
		this.notifyAll();
	}
}

3、三个售票窗口同时出售20张票。

public class Problem03 {

	public static void main(String[] args) {
		TicketOffice ticketOffice = new TicketOffice(new Object(), 20);
		new Thread(ticketOffice, "ticket-1").start();
		new Thread(ticketOffice, "ticket-2").start();
		new Thread(ticketOffice, "ticket-3").start();
	}
}

class TicketOffice implements Runnable {

	private Object object;

	private int ticketNum;

	public TicketOffice(Object object, int ticketNum) {
		this.object = object;
		this.ticketNum = ticketNum;
	}

	@Override
	public void run() {
		while (ticketNum > 0) {
			synchronized (object) {
				if (ticketNum <= 0) {
					System.out.println(Thread.currentThread().getName() + " : 没有票啦...");
				} else {
					System.out.println(Thread.currentThread().getName() + " : 卖出了第" + ticketNum-- + "张票");
					try {
						Thread.sleep(1000L);
					} catch (InterruptedException e) {
						e.printStackTrace();
					}
				}
			}
		}
	}
}