Unity下利用WinAPI打开FileDialog

最新推荐文章于 2023-12-13 18:03:30 发布

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最新推荐文章于 2023-12-13 18:03:30 发布 · 461 阅读

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CC 4.0 BY-SA版权

文章标签：

#C# #unity #打开文件 #FileDialog

本文介绍如何在Unity中通过C#调用WinAPI的GetOpenFileName函数来打开文件对话框。示例代码展示了如何设置对话框的参数，如初始目录、文件过滤器等，以及如何获取用户选择的文件路径。

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using UnityEngine;
using System.Runtime.InteropServices;
using System;

public class WinAPITest : MonoBehaviour
{


    [DllImport("Comdlg32.dll", SetLastError = true, ThrowOnUnmappableChar = true, CharSet = CharSet.Auto)]
    public static extern bool GetOpenFileName([In, Out] FileStruct ofn);
    public static bool GetOpenFileName1([In, Out] FileStruct ofn)
    {
        return GetOpenFileName(ofn);
    }

    public void OpenFileDialog()
    {
        FileStruct ofn = new FileStruct();
        ofn.structSize = Marshal.SizeOf(ofn);
        ofn.filter = "All Files\0*.*\0\0";
        ofn.file = new string(new char[256]);
        ofn.maxFile = ofn.file.Length;
        ofn.fileTitle = new string(new char[64]);
        ofn.maxFileTitle = ofn.fileTitle.Length;
        string path = Application.streamingAssetsPath;
        path = path.Replace('/', '\\');
        //默认路径  
        ofn.initialDir = path;
        ofn.title = "Open Project";
        //显示文件的类型