HDOJ2017字符串统计

题意十分简单，思路只要判断每个字符是不是数字就可以，我的代码十分易于理解，虽然没有技术含量。（可以写一个函数将判断的十个数字封装起来，这样会好看很多）

#include <iostream>
#include<stdio.h>
#include<string>
using namespace std;

int main()
{
    string a;
    int n;
    cin>>n;
    while(n--)
    {
        cin>>a;
        int len=a.length();
        int ans=0;
        for(int i=0;i<len;i++)
        {
            if(a[i]=='0')
            {
               ans++;
               continue;
            }
            if(a[i]=='1')
            {
               ans++;
               continue;
            }
            if(a[i]=='2')
            {
               ans++;
               continue;
            }
            if(a[i]=='3')
            {
                   ans++;
               continue;
            }
           if(a[i]=='4')
            {
                   ans++;
               continue;
            }
               if(a[i]=='5')
            {
                   ans++;
               continue;
            }
               if(a[i]=='6')
            {
                   ans++;
               continue;
            }
               if(a[i]=='7')
            {
                   ans++;
               continue;
            }
               if(a[i]=='8')
            {
                   ans++;
               continue;
            }
               if(a[i]=='9')
            {
                   ans++;
               continue;
            }

        }
        cout<<ans<<endl;
    }
    return 0;
}