/*
*程序的版权和版本声明部分:
*Copyright(c)2014,烟台大学计算机学院学生
*All rights reserved.
*文件名称:
*作者:王鲁峰
*完成日期:2014 年 5 月 27 日
*版本号:v1.0
*对任务及求解方法的描述部分:
*问题描述:编写一个程序,定义抽象基类Shape,由它派生出5个派生类:Circle、Square、Rectangle、Trapezoid、Triangle
用虚函数分别计算几种图形面积,并求它们之和。
要求用基类指针数组,使它每一个元素指向一个派生类对象。
*输入描述: Input
圆的半径
正方形的边长
矩形的边长
梯形的上底和下底,高
三角形的底与高
*程序输出:Output
所有图形面积之和(结果保留两位小数)
*问题分析:
*算法设计:
*/
#include <iostream>
#include <iomanip>
using namespace std;
class Shape
{
public:
virtual double area()=0;
};
class Circle:public Shape
{
public:
Circle(double R):r(R) {}
double area();
private:
double r;
};
class Square:public Shape
{
public:
Square(double a1):a(a1) {}
double area();
private:
double a;
};
class Rectangle:public Shape
{
public:
Rectangle(double l,double w):length(l),width(w) {}
double area();
private:
double length,width;
};
class Trapezoid:public Shape
{
public:
Trapezoid(double l,double w,double h):length(l),width(w),high(h) {} //分别代表上底下底还有高
double area();
private:
double length,width,high;
};
class Triangle:public Shape
{
public:
Triangle(double l,double h):length(l),high(h) {}
double area();
private:
double length,high;//分别代表底高
};
double Circle::area()
{
double s;
s=3.1415926*r*r;
return s;
}
double Square::area()
{
double s;
s=a*a;
return s;
}
double Rectangle::area()
{
double s;
s=length*width;
return s;
}
double Trapezoid::area()
{
double s;
s=(length+width)*high/2;
return s;
}
double Triangle::area()
{
double s;
s=length*high/2;
return s;
}
int main()
{
float r,a,b,w1,w2,w,h;
cout<<fixed<<setprecision(2);
cin>>r;
Circle circle(r);
cin>>a;
Square square(a);
cin>>a>>b;
Rectangle rectangle(a,b);
cin>>w1>>w2>>h;
Trapezoid trapezoid(w1,w1,h);
cin>>w>>h;
Triangle triangle(w,h);
Shape *pt[5]= {&circle,&square,&rectangle,&trapezoid,&triangle};
double areas=0.0;
for(int i=0; i<5; i++)
areas=areas+pt[i]->area();
cout<<"total of all areas="<<areas<<endl;
return 0;
}
运行结果:
心得体会:
一开始计算出来的面积是573.86,我以为是程序写错了,后来发现是PI定义的问题,应该定义成3.1415926.。。。