var url = location.search;////获取url中"?"符后的字串
var s = url.indexOf('noteid=');
var e = url.indexOf('Wfid');
var noteid = url.substring(s+7,e-1);
获取URL
最新推荐文章于 2025-03-22 00:15:29 发布
var url = location.search;////获取url中"?"符后的字串
var s = url.indexOf('noteid=');
var e = url.indexOf('Wfid');
var noteid = url.substring(s+7,e-1);