Brick Wall Patterns
If we want to build a brick wall out of the usual size of brick which has a length twice as long as its height, and if our wall is to be two units tall, we can make our wall in a number of patterns, depending on how long we want it. From the figure one observe that:

- There is just one wall pattern which is 1 unit wide - made by putting the brick on its end.
- There are 2 patterns for a wall of length 2: two side-ways bricks laid on top of each other and two bricks long-ways up put next to each other.
- There are three patterns for walls of length 3.
Problem
Your task is to write a program that given the length of a wall, determines how many patterns there may be for a wall of that length.Intput
Your program receives a sequence of positive integers, one per line, each representing the length of a wall. The maximum value for the wall is length 50. The input terminates with a 0.Output
For each wall length given in the input, your program must output the corresponding number of different patterns for such a wall in a separate line.Sample Intput
1 2 3 0
Sample Output
1 2 3
#include<iostream> using namespace std; int main() { int n,i; int a[100]; a[1]=1; a[2]=2; for(i=3;i<100;i++) { a[i]=a[i-2]+a[i-1]; } while(cin>>n) { if(n==0) break; cout<<a[n]<<endl; } return 0; }