#include<stdio.h>
int main()
{
int a[50]={0,1,1},i,n;
scanf("%d",&n);
for(i=1;i<=n;i++)
{a[i+1]=a[i-1]+a[i];
printf("%d ",a[i]);
}
return 0;
}
斐波纳契数列
最新推荐文章于 2025-02-01 16:05:57 发布
#include<stdio.h>
int main()
{
int a[50]={0,1,1},i,n;
scanf("%d",&n);
for(i=1;i<=n;i++)
{a[i+1]=a[i-1]+a[i];
printf("%d ",a[i]);
}
return 0;
}