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(uva 11729)突击战（ Commando War）
11729 - Commando WarTime limit: 1.000 secondsGCommando WarInput: Standard InputOutput: Standard Output “Waiting for orders we held in the wood, word from原创 2013-09-22 23:18:11 · 821 阅读 · 0 评论 -
(uva 11300)分金币（Spreading the Wealth）
11300 - Spreading the WealthTime limit: 6.000 seconds F. Spreading the Wealth ProblemA Communist regime is trying to redistribute wealth in a village. They have have原创 2013-09-23 00:03:28 · 603 阅读 · 0 评论 -
(uva 10881）蚂蚁（Piotr's Ants）
10881 - Piotr's AntsTime limit: 3.000 secondsProblem DPiotr's AntsTime Limit: 2 seconds"One thing is for certain: there is no stopping them;the ants will soon be here. And原创 2013-09-23 00:50:41 · 572 阅读 · 0 评论 -
(uva 11292)勇士斗恶龙（The Dragon of Loowater）
11292 - Dragon of LoowaterTime limit: 1.000 seconds#include #include using namespace std;const int maxn = 20000+5;int A[maxn], B[maxn];int main(){ int n,m; while(scanf("%d%d", &n, &原创 2013-09-16 13:41:42 · 606 阅读 · 0 评论 -
(uva 11464）偶数矩阵（Even Parity）
学位运算的时候以为用不上看了几眼直接就跳过了……结果这次吃亏了……在老师的指导下第一次学会了位运算，留念~具体见代码注释~11464 - Even ParityTime limit: 3.000 secondsDEven ParityInput: Standard InputOutput: Standard Output原创 2013-09-23 13:32:39 · 635 阅读 · 0 评论 -
uva 11384 正整数序列（ Help is needed for Dexter）
11384 - Help is needed for DexterTime limit: 3.000 secondsProblem HHelp is needed for DexterTime Limit: 3 Second Dexter is tired of Dee Dee. So he decided to keep Dee Dee busy in a g原创 2013-09-25 18:06:49 · 493 阅读 · 0 评论