字符串和数字相互转换

最新推荐文章于 2025-06-12 19:19:20 发布

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errno_t _itoa_s(  
   int value,  
   char *buffer,  
   size_t sizeInCharacters,  
   int radix   
);  
errno_t _i64toa_s(  
   __int64 value,  
   char *buffer,  
   size_t sizeInCharacters,  
   int radix   
);  
errno_t _ui64toa_s(  
   unsigned _int64 value,  
   char *buffer,  
   size_t sizeInCharacters,  
   int radix   
);  
errno_t _itow_s(  
   int value,  
   wchar_t *buffer,  
   size_t sizeInCharacters,  
   int radix   
);  
errno_t _i64tow_s(  
   __int64 value,  
   wchar_t *buffer,  
   size_t sizeInCharacters,  
   int radix   
);  
errno_t _ui64tow_s(  
   unsigned __int64 value,  
   wchar_t *buffer,  
   size_t sizeInCharacters,  
   int radix   
);  
template <size_t size>  
errno_t _itoa_s(  
   int value,  
   char (&buffer)[size],  
   int radix   
); // C++ only  
template <size_t size>  
errno_t _itow_s(  
   int value,  
   wchar_t (&buffer)[size],  
   int radix   
); // C++ only

Parameters

[in] value
Number to be converted.

[out] buffer
Filled with the result of the conversion.

[in] sizeInCharacters
Size of the buffer in single-byte characters or wide characters.

[in] radix
Base of value; which must be in the range 2–36.

Example：

#include <stdlib.h>  
#include <string.h>  
  
int main( void )  
{  
    char buffer[65];  
    int r;  
    for( r=10; r>=2; --r )  
    {  
       _itoa_s( -1, buffer, 65, r );  
       printf( "base %d: %s (%d chars)\n", r, buffer, strnlen(buffer, _countof(buffer)) );  
    }  
    printf( "\n" );  
    for( r=10; r>=2; --r )  
    {  
       _i64toa_s( -1L, buffer, 65, r );  
       printf( "base %d: %s (%d chars)\n", r, buffer, strnlen(buffer, _countof(buffer)) );  
    }  
    printf( "\n" );  
    for( r=10; r>=2; --r )  
    {  
       _ui64toa_s( 0xffffffffffffffffL, buffer, 65, r );  
       printf( "base %d: %s (%d chars)\n", r, buffer, strnlen(buffer, _countof(buffer)) );  
    }  
}

详见https://msdn.microsoft.com/en-us/library/0we9x30h.aspx