CodeForces – 1013A A. Piles With Stones

本文介绍了一个简单的编程问题,参与者记录了石头堆的变化情况,并通过编程判断这些记录是否合理。问题的关键在于检查前后两天石头总数的变化。

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There is a beautiful garden of stones in Innopolis.

Its most beautiful place is the nn piles with stones numbered from 11 to nn.

EJOI participants have visited this place twice.

When they first visited it, the number of stones in piles was x1,x2,…,xnx1,x2,…,xn, correspondingly. One of the participants wrote down this sequence in a notebook.

They visited it again the following day, and the number of stones in piles was equal to y1,y2,…,yny1,y2,…,yn. One of the participants also wrote it down in a notebook.

It is well known that every member of the EJOI jury during the night either sits in the room 108108 or comes to the place with stones. Each jury member who comes there either takes one stone for himself or moves one stone from one pile to another. We can assume that there is an unlimited number of jury members. No one except the jury goes to the place with stones at night.

Participants want to know whether their notes can be correct or they are sure to have made a mistake.

 

Input

The first line of the input file contains a single integer nn, the number of piles with stones in the garden (1≤n≤501≤n≤50).

The second line contains nn integers separated by spaces x1,x2,…,xnx1,x2,…,xn, the number of stones in piles recorded in the notebook when the participants came to the place with stones for the first time (0≤xi≤10000≤xi≤1000).

The third line contains nn integers separated by spaces y1,y2,…,yny1,y2,…,yn, the number of stones in piles recorded in the notebook when the participants came to the place with stones for the second time (0≤yi≤10000≤yi≤1000).

Output

If the records can be consistent output “Yes”, otherwise output “No” (quotes for clarity).

Examples

input

Copy

5
1 2 3 4 5
2 1 4 3 5

output

Copy

Yes

input

Copy

5
1 1 1 1 1
1 0 1 0 1

output

Copy

Yes

input

Copy

3
2 3 9
1 7 9

output

Copy

No

Note

In the first example, the following could have happened during the night: one of the jury members moved one stone from the second pile to the first pile, and the other jury member moved one stone from the fourth pile to the third pile.

In the second example, the jury took stones from the second and fourth piles.

It can be proved that it is impossible for the jury members to move and took stones to convert the first array into the second array.

题目分析:吐槽!!!!题面看了老半天才看懂。。。明明就是个入门水题。。

有些人两次观察石头,首先,他们在观察石头。对于这么多堆的石头,他们在第二天可以移动石头到另一堆或直接拿走。问他们的观察每堆石头数量的记录是否有问题。如果是移动则总数不变,如果拿走则总数减少,所以第二堆石头一定不可能比第一堆多。所以我们只要比较第一天与第二天的数量之和就可以了,只要第一天的总和大于等于第二天,那么就是对的。

#include<iostream>
using namespace std;
int main()
{
    int n;
    while(cin>>n)
  {
        int sum1=0,sum2=0;
        int a;
        for(int i=0;i<n;i++){
            cin>>a;
            sum1=sum1+a;
        }
        for(int i=0;i<n;i++){
            cin>>a;
            sum2=sum2+a;
        }
        if(sum2<=sum1)cout<<"Yes"<<endl;
        else cout<<"No"<<endl;
    }
    return 0;
}

 

内容概要:该论文探讨了一种基于粒子群优化(PSO)的STAR-RIS辅助NOMA无线通信网络优化方法。STAR-RIS作为一种新型可重构智能表面,能同时反射和传输信号,与传统仅能反射的RIS不同。结合NOMA技术,STAR-RIS可以提升覆盖范围、用户容量和频谱效率。针对STAR-RIS元素众多导致获取完整信道状态信息(CSI)开销大的问题,作者提出一种在不依赖完整CSI的情况下,联合优化功率分配、基站波束成形以及STAR-RIS的传输和反射波束成形向量的方法,以最大化总可实现速率并确保每个用户的最低速率要求。仿真结果显示,该方案优于STAR-RIS辅助的OMA系统。 适合人群:具备一定无线通信理论基础、对智能反射面技术和非正交多址接入技术感兴趣的科研人员和工程师。 使用场景及目标:①适用于希望深入了解STAR-RIS与NOMA结合的研究者;②为解决无线通信中频谱资源紧张、提高系统性能提供新的思路和技术手段;③帮助理解PSO算法在无线通信优化问题中的应用。 其他说明:文中提供了详细的Python代码实现,涵盖系统参数设置、信道建模、速率计算、目标函数定义、约束条件设定、主优化函数设计及结果可视化等环节,便于读者理解和复现实验结果。此外,文章还对比了PSO与其他优化算法(如DDPG)的区别,强调了PSO在不需要显式CSI估计方面的优势。
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