G - Ternary Calculation（水）

最新推荐文章于 2024-09-03 08:30:00 发布

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最新推荐文章于 2024-09-03 08:30:00 发布

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分类专栏：比赛

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本文介绍了一个算法，用于解析并计算包含三个操作数和两个运算符的表达式。该算法支持加、减、乘、除及取余运算，并通过多个样例展示了其正确性和实用性。

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Description

Complete the ternary calculation.

Input

There are multiple test cases. The first line of input contains an integer T indicating the number of test cases. For each test case:

There is a string in the form of "number₁operator_anumber₂operator_bnumber₃". Each operator will be one of {'+', '-' , '*', '/', '%'}, and each number will be an integer in [1, 1000].

Output

For each test case, output the answer.

Sample Input

Sample Output

Note

The calculation "A % B" means taking the remainder of A divided by B, and "A / B" means taking the quotient.

#include <iostream>
#include <cstring>
#include <algorithm>
#include <cstring>
#include<cstdio>
using namespace std;
int main()
{
    int n;
    while(scanf("%d",&n)!=EOF)
    {
        getchar();
        while(n--)
        {
            int a,b,c;
            char s1,s2;
            int sum=0;
            cin>>a>>s1>>b>>s2>>c;
            if(s1=='*')
            {
                sum=a*b;
                if(s2=='-')
                    sum-=c;
                else if(s2=='+')
                    sum+=c;
                else if(s2=='%')
                    sum%=c;
                else if(s2=='*')
                    sum*=c;
                else if(s2=='/')
                    sum/=c;
                cout<<sum<<endl;
            }
            else if(s1=='/')
            {
                sum=a/b;
                if(s2=='-')
                    sum-=c;
                else if(s2=='+')
                    sum+=c;
                else if(s2=='%')
                    sum%=c;
                else if(s2=='*')
                    sum*=c;
                else if(s2=='/')
                    sum/=c;
                printf("%d\n",sum);
            }
            else if(s1=='%')
            {
                sum=a%b;
                if(s2=='-')
                    sum-=c;
                else if(s2=='+')
                    sum+=c;
                else if(s2=='%')
                    sum%=c;
                else if(s2=='*')
                    sum*=c;
                else if(s2=='/')
                    sum/=c;
                printf("%d\n",sum);
            }
            else if(s1=='+')
            {
                if(s2=='-')
                    sum=b-c;
                else if(s2=='+')
                    sum=b+c;
                else if(s2=='%')
                    sum=b%c;
                else if(s2=='*')
                    sum=b*c;
                else if(s2=='/')
                    sum=b/c;
                sum+=a;
                printf("%d\n",sum);
            }
            else if(s1=='-')
            {
                if(s2=='-')
                    sum=a-b-c;
                else if(s2=='+')
                    sum=a-b+c;
                else if(s2=='%')
                    sum=a-(b%c);
                else if(s2=='*')
                    sum=a-(b*c);
                else if(s2=='/')
                    sum=a-(b/c);

                printf("%d\n",sum);
            }
        }
    }

    return 0;
}