class Solution {
public:
/**
* @param num: the rotated sorted array
* @return: the minimum number in the array
*/
int findMin(vector<int> &num) {
// write your code here
int pre=num[0];
for(int i=1;i<num.size();i++){
if(pre>num[i])
return num[i];
}
return pre;
}
};
LintCode-剑指Offer-(160)寻找旋转排序数组中的最小值Ⅱ
