题目链接:uva 12275 - Sensor network
先建立最小生成树,然后枚举边,加入树中,如果形成环,就将环生权值最小的边删除。
#include <cstdio>
#include <cstring>
#include <vector>
#include <set>
#include <algorithm>
using namespace std;
typedef pair<int,int> pii;
const int maxn = 400;
const int maxm = maxn * maxn >> 1;
const int inf = 0x3f3f3f3f;
struct Edge {
int u, v, d, idx;
Edge(int u = 0, int v = 0, int d = 0, int idx = 0): u(u), v(v), d(d), idx(idx) {}
bool operator < (const Edge& a) const { return idx < a.idx; }
}E[maxm];
int N, M, F[maxn], vi[maxm];
set<Edge> S;
set<pii> G[maxn];
typedef set<Edge>::iterator iter;
bool cmp(const Edge& a, const Edge& b) { return a.d < b.d; }
int find(int x) { return x == F[x] ? x : F[x] = find(F[x]); }
void addEdge (int i) {
S.insert(E[i]);
G[E[i].u].insert(make_pair(E[i].v, i));
G[E[i].v].insert(make_pair(E[i].u, i));
}
void eraseEdge(int i) {
S.erase(E[i]);
G[E[i].u].erase(make_pair(E[i].v, i));
G[E[i].v].erase(make_pair(E[i].u, i));
}
int C;
Edge temp[maxn];
bool dfs (int u, int fa, int e) {
if (u == e) return true;
for (set<pii>::iterator i = G[u].begin(); i != G[u].end(); i++) {
int v = i->first;
if (v == fa) continue;
temp[C++] = E[i->second];
if (dfs(v, u, e)) return true;
C--;
}
return false;
}
int findMinEdge(int u, int v) {
C = 0;
dfs(u, -1, v);
sort(temp, temp + C, cmp);
return temp[0].idx;
}
int solve () {
S.clear();
for (int i = 0; i < N; i++)
F[i] = i, G[i].clear();
memset(vi, 0, sizeof(vi));
int n = N, l = inf, ans;
for (int i = 0; i < M; i++) E[i].idx = i;
for (int i = 0; i < M; i++) {
int u = E[i].u, v = E[i].v, d = E[i].d;
if (find(u) != find(v)) {
n--;
vi[i] = 1;
l = min(l, d);
F[find(u)] = find(v);
addEdge(i);
if (n == 1) {
ans = d - l;
break;
}
}
}
for (int i = 0; i < M; i++) if (!vi[i]) {
int u = E[i].u, v = E[i].v, d = E[i].d;
int t = findMinEdge(u, v);
if (E[t].d >= d) continue;
eraseEdge(t);
addEdge(i);
int l = inf, r = 0;
for (iter it = S.begin(); it != S.end(); it++) {
l = min(l, it->d);
r = max(r, it->d);
}
ans = min(ans, r - l);
}
return ans;
}
int main () {
while (scanf("%d", &N) == 1 && N) {
scanf("%d", &M);
for (int i = 0; i < M; i++)
scanf("%d%d%d", &E[i].u, &E[i].v, &E[i].d);
sort(E, E + M, cmp);
printf("%d\n", solve());
}
return 0;
}