1. string转const char*
string s = "abc";
const char* c_s = s.c_str();
2. const char*转string
直接赋值即可
const char* c_s = "abc";
string s(c_s);
3. string转char*
string s = "abc";
char* c;
const int len = s.length();
c = new char[len+1];
strcpy(c,s.c_str());
4. char*转string
char* c = "abc";
string s(c);
5. const char*转char*
const char* cpc = "abc";
char* pc = new char[100];//足够长
strcpy(pc,cpc);
strcpy(pc,cpc)是copy cpc to pc,但是遇到\0就会作为结束符结束拷贝,当cpc是包含很多个结束符时,逻辑错误,所以有的时候需要用
pc = const_cast<char*>(cpc.c_str())
6. char*转const char*
直接赋值即可
char* pc = "abc";
const char* cpc = pc;
7. string转char[]
char str[31];
cin.get(str,31)