https://leetcode.com/problems/divide-two-integers/
非常想知道有什么不用long long就可以A掉的方法,似乎没有
我写的: 模拟除法,学过汇编应该很容易理解
需要特殊判断的是:
如果被除数是-2147483648
const int MAX_INT = 2147483647;
const int MIN_INT = -2147483648;
class Solution {
public:
int divide(int dividend, int divisor) {
long long div = dividend, dis = divisor;
int flag = ((div > 0 && dis > 0) || (div < 0 && dis < 0)) ? 1 : -1;
if(div<0) div = -div;
if(dis<0) dis = -dis;
if(dis == 0) return MAX_INT;
if(dividend == MIN_INT) {
if(divisor == 1) return dividend;
if(divisor == -1) return MAX_INT;
}
long long ret = 0;
for(int i=31; i>=0; i--) {
long long tmp = (long long)(dis<<i);
if(div >= tmp) {
ret += (1<<i);
div -= tmp;
//cout << "tmp=" << tmp << " div=" << div << endl;
}
}
ret *= flag;
cout << ret << " ret" << endl;
if(ret >=MAX_INT || ret < MIN_INT) return MAX_INT;
return ret;
}
};