leetcode1108. Defanging an IP Address

题目：
Given a valid (IPv4) IP address, return a defanged version of that IP address.

A defanged IP address replaces every period “.” with “[.]”.

Example 1:

Input: address = “1.1.1.1”
Output: “1[.]1[.]1[.]1”
Example 2:

Input: address = “255.100.50.0”
Output: “255[.]100[.]50[.]0”

Constraints:

The given address is a valid IPv4 address.

解答1：

class Solution {
    public String defangIPaddr(String address) {
        StringBuilder result = new StringBuilder();
        char[] addArr =address.toCharArray();
        
        for(int i =0;i<addArr.length;i++){
            if(addArr[i]=='.'){
                result.append("[.]");
            }else
            {
                 result.append(addArr[i]);
            }
        }
        return result.toString();
        
    }
}

解答2：

class Solution {
    public String defangIPaddr(String address) {
       return address.replaceAll("\\.","\\[\\.\\]");
        
    }
}