寻找&星空の孩子

【分析】 　　先看一种简单的情况：甲和乙的路线都是一条线段。因为运动是相对的，因此也可以认为甲静止不动，乙沿着自己的直线走，因此问题转化为求点到线段的最小距离和最大距离；　　有了简化版的分析，只需要模拟整个过程，设现在甲的位置在Pa，刚刚经过编号为Sa的拐点；乙的位置是Pb，刚刚经过编号为Sb的拐点，则我们只需要计算他们俩谁先到拐点，那么在这个时间点之前的问题就是我们刚刚讨论过的“简化版”。求

1503: 点到圆弧的距离Time Limit: 1 Sec  Memory Limit: 128 MB  Special JudgeSubmit: 325  Solved: 70[Submit][Status][Web Board]Description输入一个点P和一条圆弧（圆周的一部分），你的任务是计算P到圆弧的最短距离。换句话说，你需要在圆弧上找一个点，到P

Problem 2148 Moon GameAccept: 24 Submit: 61 Time Limit: 1000 mSec Memory Limit : 32768 KBProblem DescriptionFat brother and Maze are playing a kind of special (hentai) game in the clearl

You can Solve a Geometry Problem tooTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 6837 Accepted Submission(s): 3303Problem Description

Lifting the StoneTime Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 5370 Accepted Submission(s): 2239Problem DescriptionThere are many secr

Incircle and CircumcircleTime Limit: 2 Seconds Memory Limit: 65536 KB Special JudgeA triangle is one the basic shapes in geometry. It's a polygon with three vertices and three sides which are line s

题意：Morley定理，求D、E、F的坐标思路：没什么算法，就是几何的应用。注意旋转角就好了。转载请注明出处：寻找&星空の孩子 题目链接：UVA11178  #include#include#define PI acos(-1.0)using namespace std;struct Point{ double x,y; Point(double

Viva ConfettiTime Limit:3000MS     Memory Limit:0KB     64bit IO Format:%lld & %lluSubmit Status Practice UVALive 2572Appoint description: System Crawler  (2015-04-19)Description

Aquarium TankTime Limit: 1 Sec  Memory Limit: 128 MBSubmit: 15  Solved: 4[Submit][Status][Web Board]DescriptionYou just bought an “artistic” aquarium tank that has an interesting shape,