UVa10474 Where is the Marble?

本文介绍了一个寻找特定编号大理石的游戏算法。玩家需要在一个无序的数字列表中找出目标数字的位置或确认其不存在。通过排序和搜索策略,实现快速定位,适用于算法初学者实践。


 Where is the Marble? 

Raju and Meena love to play with Marbles. They have got a lotof marbles with numbers written on them. At the beginning, Rajuwould place the marbles one after another in ascending order ofthe numbers written on them. Then Meena would ask Raju tofind the first marble with a certain number. She would count1...2...3. Raju gets one point for correct answer, and Meena getsthe point if Raju fails. After some fixed number of trials thegame ends and the player with maximum points wins. Today it'syour chance to play as Raju. Being the smart kid, you'd be takingthe favor of a computer. But don't underestimate Meena, she hadwritten a program to keep track how much time you're taking togive all the answers. So now you have to write a program, whichwill help you in your role as Raju.

Input 

There can be multiple test cases. Total no of test cases is less than 65. Each test case consistsbegins with 2 integers: N the number of marbles and Q the number of queries Mina wouldmake. The next N lines would contain the numbers written on the N marbles. These marblenumbers will not come in any particular order. Following Q lines will have Q queries. Beassured, none of the input numbers are greater than 10000 and none of them are negative.

Input is terminated by a test case where N = 0 and Q = 0.

Output 

For each test case output the serial number of the case.

For each of the queries, print one line of output. The format of this line will depend uponwhether or not the query number is written upon any of the marbles. The two different formatsare described below:

  • `x found at y', if the first marble with number x was found at position y.Positions are numbered 1, 2,..., N.
  • `x not found', if the marble with number x is not present.

Look at the output for sample input for details.

Sample Input 

4 1
2
3
5
1
5
5 2
1
3
3
3
1
2
3
0 0

Sample Output 

CASE# 1:
5 found at 4
CASE# 2:
2 not found
3 found at 3


Problem-setter: Monirul Hasan Tomal, Southeast University


这题大意就是给你一串的数字,然后再给定一个数字,要求你输出这数字在这串数字中大小的排名。简单的排完,就能找到了,具体也就输出的格式要注意下。

#include<iostream>
#include<cstdlib>
using namespace std;

const int N = 10000;
int s[N];
int p;

int cmp(const void *a,const void *b){
	return *(int*)a - *(int*)b;
}

int main(){
	int n;
	int q;
	int num = 1;
	while (cin >> n >> q){
		if (!n && !q)
			break;
		int i;
		int j;
		int s_len;
		for (i = 0; i < n; i++)
			cin >> s[i];
		s_len = i;
		cout << "CASE# " << num << ":" << endl;
		num++;
		qsort(s,s_len,sizeof(int),cmp);
		for (i = 0; i < q; i++) {
			cin >> p;
			for (j = 0; j < n; j++){
				if (p == s[j]){
					cout << p << " found at " << j+1 << endl;
					break;
				}
			}
			if (j == n)
				cout << p << " not found" << endl;
		}
	}
	return 0;
}


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