如何循环获取html的值,并拼写到json/json,求value所对应key的值

本文介绍了一种从HTML表格中解析数据并将其转换为JSON格式的方法。通过使用jQuery库遍历HTML元素,实现了将每行数据转换为JSON对象的过程。此外,还提供了一个查找JSON值对应键名的实用函数。
有如下html结构
<tr>
<span class="originalAirportId">123</span>
<span class="airportName">123</span>
<span class="cityName">123</span>
<span class="provinceName">123</span>
<span class="provinceId">123</span>
<span class="countryId">123</span>
<span class="countryName">123</span>
</tr>
<tr>
<span class="originalAirportId">123</span>
<span class="airportName">123</span>
<span class="cityName">123</span>
<span class="provinceName">123</span>
<span class="provinceId">123</span>
<span class="countryId">123</span>
<span class="countryName">123</span>
</tr>
<tr>
<span class="originalAirportId">123</span>
<span class="airportName">123</span>
<span class="cityName">123</span>
<span class="provinceName">123</span>
<span class="provinceId">123</span>
<span class="countryId">123</span>
<span class="countryName">123</span>
</tr>
.....
.....
.....
<tr>标签个数不确定
要求得到如下的json
{
    "airportList": [
        {
            "originalAirportId": "123",
            "airportName": "asdf",
            "cityName": "qwer",
            "cityId": "qwer",
            "provinceName": "qwer",
            "provinceId": "qwer",
            "countryId": "qwer",
            "countryName": "qwer"
        },
        {
            "originalAirportId": "123",
            "airportName": "asdf",
            "cityName": "qwer",
            "cityId": "qwer",
            "provinceName": "qwer",
            "provinceId": "qwer",
            "countryId": "qwer",
            "countryName": "qwer"
        }
    ]

}

<table id="tb"><tr><td>
    <span class="originalAirportId">123</span>
    <span class="airportName">123</span>
    <span class="cityName">123</span>
    <span class="provinceName">123</span>
    <span class="provinceId">123</span>
    <span class="countryId">123</span>
    <span class="countryName">123</span>
</td>
</tr>
<tr><td>
    <span class="originalAirportId">123</span>
    <span class="airportName">123</span>
    <span class="cityName">123</span>
    <span class="provinceName">123</span>
    <span class="provinceId">123</span>
    <span class="countryId">123</span>
    <span class="countryName">123</span>
</td>
</tr>
<tr><td>
    <span class="originalAirportId">123</span>
    <span class="airportName">123</span>
    <span class="cityName">123</span>
    <span class="provinceName">123</span>
    <span class="provinceId">123</span>
    <span class="countryId">123</span>
    <span class="countryName">123</span>
</td>
</tr></table>
<script type="text/javascript" src="http://ajax.aspnetcdn.com/ajax/jQuery/jquery-1.4.2.min.js"></script>
<script>
    var o = {airportList:[]};
    $('#tb').find('tr').each(function () { var item = {}; $('span', this).each(function () { item[this.className] = this.innerHTML }); o.airportList.push(item) });
    console.log(o)
</script>


求value所对应key的值.
var findkey={"firstName":"Brett","lastName":"McLaughlin","email":"aaaa"};

function find(value){
                var findkey={"firstName":"Brett","lastName":"McLaughlin","email":"aaaa"};
                for(var key in findkey){
                    if(findkey[key] == value)
                        return key;
                }
                return null;
        }
        alert(find("aaaa"));

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