-
long long getCurrentTime() { struct timeval tv; gettimeofday(&tv,NULL); return tv.tv_sec * 1000 + tv.tv_usec / 1000; }
C++获取系统的毫秒时间
最新推荐文章于 2024-12-30 10:30:34 发布
long long getCurrentTime()
{
struct timeval tv;
gettimeofday(&tv,NULL);
return tv.tv_sec * 1000 + tv.tv_usec / 1000;
}