UVa458 - The Decoder-字符串-难度1_write a complete program that will correctly decod-优快云博客

本文链接：https://blog.youkuaiyun.com/li_jiakang/article/details/17427267

本文介绍了一个简单的字符解码程序，该程序能够正确解码特定格式的字符集并还原为原始消息。通过简单的算术操作实现ASCII字符集的一对一替换。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

题目链接：

http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=94&page=show_problem&problem=399

The Decoder

Write a complete program that will correctly decode a set of characters into a valid message. Your program should read a given file of a simple coded set of characters and print the exact message that the characters contain. The code key for this simple coding is a one for one character substitution based upon a single arithmetic manipulation of the printable portion of the ASCII character set.

Input and Output

For example: with the input file that contains:

1JKJ'pz'{ol'{yhklthyr'vm'{ol'Jvu{yvs'Kh{h'Jvywvyh{pvu5
1PIT'pz'h'{yhklthyr'vm'{ol'Pu{lyuh{pvuhs'I|zpulzz'Thjopul'Jvywvyh{pvu5
1KLJ'pz'{ol'{yhklthyr'vm'{ol'Kpnp{hs'Lx|pwtlu{'Jvywvyh{pvu5

your program should print the message:

*CDC is the trademark of the Control Data Corporation.
*IBM is a trademark of the International Business Machine Corporation.
*DEC is the trademark of the Digital Equipment Corporation.

Your program should accept all sets of characters that use the same encoding scheme and should print the actual message of each set of characters.

Sample Input

1JKJ'pz'{ol'{yhklthyr'vm'{ol'Jvu{yvs'Kh{h'Jvywvyh{pvu5
1PIT'pz'h'{yhklthyr'vm'{ol'Pu{lyuh{pvuhs'I|zpulzz'Thjopul'Jvywvyh{pvu5
1KLJ'pz'{ol'{yhklthyr'vm'{ol'Kpnp{hs'Lx|pwtlu{'Jvywvyh{pvu5

Sample Output

*CDC is the trademark of the Control Data Corporation.
*IBM is a trademark of the International Business Machine Corporation.
*DEC is the trademark of the Digital Equipment Corporation.

代码：

#include <iostream>
#include <string>
#include <cstdio>
#include <cctype>
using namespace std;

int main()
{
#ifdef LOCAL
	freopen("f:\\input.txt", "r", stdin);
#endif LOCAL
	
	char c;
	while(scanf("%c", &c) != EOF)
	{//使用scanf适合输入一段的字符串
		if(c == '\n')
		{
			printf("\n");
			continue;
		}
		else
		{
			printf("%c", c - 7);
		}
	}
	return 0;
}