3Sum Closest

寻找最接近目标的三数之和

Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.

    For example, given array S = {-1 2 1 -4}, and target = 1.

    The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).

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package leetcode;

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;

/**
 * 
 * @author Mouse
 *
 */
public class Solution {
	public static int threeSumClosest(int[] nums, int target) {
		if (nums == null || nums.length < 3)
			return nums[0] + nums[1];
		Arrays.sort(nums);// 给nums排序
		int min = nums[0] + nums[1] + nums[2];
		for (int i = 0; i < nums.length; i++) {
			int left = i + 1;
			int right = nums.length - 1;
			while (left < right) {
				int sum = nums[left] + nums[right] + nums[i];
				int differ1 = sum - target;
				differ1 = differ1 > 0 ? differ1 : -differ1;
				int differ2 = min - target;
				differ2 = differ2 > 0 ? differ2 : -differ2;
				if (differ1 < differ2) {
					min = sum;
				} 
				if (sum < target) {
					left++;
				} else {
					right--;

				}
			}

		}
		return min;

	}

	public static void main(String[] args) {
		// 1, 1, 1, 0 -100
		// 0,2,1,-3 1
		int[] nums = { 0, 2, 1, -3 };
		int a = threeSumClosest(nums, 1);
		System.out.println(a);

	}

}




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